Algebra Seminar

Tuesday, February 25, 2020 2:30 pm - 2:30 pm EST (GMT -05:00)

Ehsaan Hossain, Department of Pure Mathematics, University of Waterloo

"Return Sets on Algebraic Varieties"

Let $\varphi:X\rightarrow X$ be an algebraic mapping of an algebraic variety $X$, so that each point $x\in X$ has an orbit $\{x,\varphi(x),\varphi^2(x),\ldots\}$. We consider the set of ``times'' when the orbit of $x$ returns to a given closed set $C$: $$E=E_\varphi(x,C) = \{n\in \mathbb{N} : \varphi^n(x)\in C\}.$$ This is called an \textbf{algebraic return set}. Our main question is: which subsets of $\mathbb{N}$ can appear as algebraic return sets? It is conjectured that $E$ can only be infinite if it contains an infinite arithmetic progression, which means that $x$ must return to $C$ periodically.

In 2014, Bell--Ghioca--Tucker proved this periodicity when $E$ has \textit{positive density}. Here the \textbf{density} of a set $S\subseteq \mathbb{N}$ is defined to be the limiting proportion of members of $S$ amongst the first $n$ integers: $$\delta(S) = \limsup_{n\rightarrow\infty}\frac{|S\cap \{1,\ldots,n\}|}{n}.$$ But their theorem does not rule out infinite zero-density sets such as $T=\{ n\in \mathbb{N} : \text{the $3$-ary expansion of $n$ contains no $2$'s}\}$, which is an ``automatic'' set containing no arithmetic progression --- can this $T$ be a return set? We will show that it is not by adapting BGT's proof, realizing their argument as a disguised version of the Poincar\'{e} Recurrence Theorem from ergodic theory.

MC 5403